N=1/2(n^2-n)

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Solution for N=1/2(n^2-n) equation: 


x in (-oo:+oo)

N = (1/2)*(n^2-n) // - (1/2)*(n^2-n)

N-((1/2)*(n^2-n)) = 0

(-1/2)*(n^2-n)+N = 0

N-1/2*(n^2-n) = 0

N-1/2*(n^2-n) = 0

N-1/2*n^2+1/2*n = 0

N-1/2*n^2+1/2*n = 0

x belongs to the empty set

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